Base | Representation |
---|---|
bin | 10011001101101010… |
… | …01100000000101101 |
3 | 222121212210002101111 |
4 | 21212311030000231 |
5 | 132111134402303 |
6 | 4423321312021 |
7 | 513422233453 |
oct | 114665140055 |
9 | 28555702344 |
10 | 10315153453 |
11 | 44136a9510 |
12 | 1bba635611 |
13 | c850926c7 |
14 | 6dbd5c9d3 |
15 | 4058b1b6d |
hex | 266d4c02d |
10315153453 has 4 divisors (see below), whose sum is σ = 11252894688. Its totient is φ = 9377412220.
The previous prime is 10315153397. The next prime is 10315153483. The reversal of 10315153453 is 35435151301.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 10315153453 - 233 = 1725218861 is a prime.
It is a super-3 number, since 3×103151534533 (a number of 31 digits) contains 333 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (10315153483) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 468870601 + ... + 468870622.
It is an arithmetic number, because the mean of its divisors is an integer number (2813223672).
Almost surely, 210315153453 is an apocalyptic number.
It is an amenable number.
10315153453 is a deficient number, since it is larger than the sum of its proper divisors (937741235).
10315153453 is an equidigital number, since it uses as much as digits as its factorization.
10315153453 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 937741234.
The product of its (nonzero) digits is 13500, while the sum is 31.
The spelling of 10315153453 in words is "ten billion, three hundred fifteen million, one hundred fifty-three thousand, four hundred fifty-three".
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