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10315502026113 = 341102182140911
BaseRepresentation
bin1001011000011100001111…
…0101010111110110000001
31100112011010001221210121210
42112013003311113312001
52323002122004313423
633534513132240333
72113161520332234
oct226070365276601
940464101853553
1010315502026113
113317863a72a49
1211a72689100a9
1359a99481753b
142793b701741b
1512d4e352eb93
hex961c3d57d81

10315502026113 has 16 divisors (see below), whose sum is σ = 14103266026752. Its totient is φ = 6702698256000.

The previous prime is 10315502026057. The next prime is 10315502026117. The reversal of 10315502026113 is 31162020551301.

10315502026113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 10315502026113 - 213 = 10315502017921 is a prime.

It is not an unprimeable number, because it can be changed into a prime (10315502026117) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 40944873 + ... + 41196038.

It is an arithmetic number, because the mean of its divisors is an integer number (881454126672).

Almost surely, 210315502026113 is an apocalyptic number.

It is an amenable number.

10315502026113 is a deficient number, since it is larger than the sum of its proper divisors (3787764000639).

10315502026113 is a wasteful number, since it uses less digits than its factorization.

10315502026113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 82141976.

The product of its (nonzero) digits is 5400, while the sum is 30.

Adding to 10315502026113 its reverse (31162020551301), we get a palindrome (41477522577414).

The spelling of 10315502026113 in words is "ten trillion, three hundred fifteen billion, five hundred two million, twenty-six thousand, one hundred thirteen".

Divisors: 1 3 41 123 1021 3063 41861 125583 82140911 246422733 3367777351 10103332053 83865870131 251597610393 3438500675371 10315502026113