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1032012131001 = 3344004043667
BaseRepresentation
bin11110000010010001011…
…01110110101010111001
310122122210200220011200120
433001020231312222321
5113402030101143001
62110033321323453
7134363136243015
oct17011055665271
93578720804616
101032012131001
11368745a41805
12148016936589
137641a4947a7
1437d41bc7545
151bca1d4c236
hexf048b76ab9

1032012131001 has 4 divisors (see below), whose sum is σ = 1376016174672. Its totient is φ = 688008087332.

The previous prime is 1032012130999. The next prime is 1032012131011. The reversal of 1032012131001 is 1001312102301.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1032012131001 - 21 = 1032012130999 is a prime.

It is not an unprimeable number, because it can be changed into a prime (1032012131011) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 172002021831 + ... + 172002021836.

It is an arithmetic number, because the mean of its divisors is an integer number (344004043668).

Almost surely, 21032012131001 is an apocalyptic number.

It is an amenable number.

1032012131001 is a deficient number, since it is larger than the sum of its proper divisors (344004043671).

1032012131001 is an equidigital number, since it uses as much as digits as its factorization.

1032012131001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 344004043670.

The product of its (nonzero) digits is 36, while the sum is 15.

Adding to 1032012131001 its reverse (1001312102301), we get a palindrome (2033324233302).

The spelling of 1032012131001 in words is "one trillion, thirty-two billion, twelve million, one hundred thirty-one thousand, one".

Divisors: 1 3 344004043667 1032012131001