Base | Representation |
---|---|
bin | 10111011101110001101111… |
… | …011001011010111001100010 |
3 | 111112101221201001012012200002 |
4 | 113131301233121122321202 |
5 | 102011322322314414132 |
6 | 1003254013104100002 |
7 | 30511023326540063 |
oct | 2735615731327142 |
9 | 445357631165602 |
10 | 103201343123042 |
11 | 2a97949781529a |
12 | b6a9141004602 |
13 | 4577aca31b178 |
14 | 1b6ad8633456a |
15 | bde785345262 |
hex | 5ddc6f65ae62 |
103201343123042 has 4 divisors (see below), whose sum is σ = 154802014684566. Its totient is φ = 51600671561520.
The previous prime is 103201343122973. The next prime is 103201343123107. The reversal of 103201343123042 is 240321343102301.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 102883877362561 + 317465760481 = 10143169^2 + 563441^2 .
It is a junction number, because it is equal to n+sod(n) for n = 103201343122996 and 103201343123014.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25800335780759 + ... + 25800335780762.
Almost surely, 2103201343123042 is an apocalyptic number.
103201343123042 is a deficient number, since it is larger than the sum of its proper divisors (51600671561524).
103201343123042 is an equidigital number, since it uses as much as digits as its factorization.
103201343123042 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 51600671561523.
The product of its (nonzero) digits is 10368, while the sum is 29.
Adding to 103201343123042 its reverse (240321343102301), we get a palindrome (343522686225343).
The spelling of 103201343123042 in words is "one hundred three trillion, two hundred one billion, three hundred forty-three million, one hundred twenty-three thousand, forty-two".
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