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1032201131207 = 1126191661587
BaseRepresentation
bin11110000010100111111…
…10110101010011000111
310122200021212112101020012
433001103332311103013
5113402421442144312
62110104152300435
7134400622565021
oct17012376652307
93580255471205
101032201131207
113688326a1424
1214806a0a171b
137644a69a12c
1437d5cd45011
151bcb3732322
hexf053fb54c7

1032201131207 has 4 divisors (see below), whose sum is σ = 1032292804056. Its totient is φ = 1032109458360.

The previous prime is 1032201131197. The next prime is 1032201131233. The reversal of 1032201131207 is 7021311022301.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1032201131207 - 28 = 1032201130951 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1032201131237) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 45819533 + ... + 45842054.

It is an arithmetic number, because the mean of its divisors is an integer number (258073201014).

Almost surely, 21032201131207 is an apocalyptic number.

1032201131207 is a deficient number, since it is larger than the sum of its proper divisors (91672849).

1032201131207 is an equidigital number, since it uses as much as digits as its factorization.

1032201131207 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 91672848.

The product of its (nonzero) digits is 504, while the sum is 23.

Adding to 1032201131207 its reverse (7021311022301), we get a palindrome (8053512153508).

The spelling of 1032201131207 in words is "one trillion, thirty-two billion, two hundred one million, one hundred thirty-one thousand, two hundred seven".

Divisors: 1 11261 91661587 1032201131207