Base | Representation |
---|---|
bin | 110000000100010110… |
… | …0100100000111111011 |
3 | 100212102221021011111021 |
4 | 1200020230210013323 |
5 | 3142401112141011 |
6 | 115230532243311 |
7 | 10313005000345 |
oct | 1401054440773 |
9 | 325387234437 |
10 | 103225115131 |
11 | 3a860982906 |
12 | 18009a70537 |
13 | 9970a329a8 |
14 | 4dd3506295 |
15 | 2a42449471 |
hex | 1808b241fb |
103225115131 has 8 divisors (see below), whose sum is σ = 105048900864. Its totient is φ = 101411604840.
The previous prime is 103225115107. The next prime is 103225115171. The reversal of 103225115131 is 131511522301.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 103225115131 - 25 = 103225115099 is a prime.
It is a super-2 number, since 2×1032251151312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 103225115096 and 103225115105.
It is not an unprimeable number, because it can be changed into a prime (103225115171) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2548591 + ... + 2588776.
It is an arithmetic number, because the mean of its divisors is an integer number (13131112608).
Almost surely, 2103225115131 is an apocalyptic number.
103225115131 is a deficient number, since it is larger than the sum of its proper divisors (1823785733).
103225115131 is an equidigital number, since it uses as much as digits as its factorization.
103225115131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5137721.
The product of its (nonzero) digits is 900, while the sum is 25.
Adding to 103225115131 its reverse (131511522301), we get a palindrome (234736637432).
The spelling of 103225115131 in words is "one hundred three billion, two hundred twenty-five million, one hundred fifteen thousand, one hundred thirty-one".
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