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103231001103 = 334410333701
BaseRepresentation
bin110000000100100001…
…1000001001000001111
3100212110100100012112020
41200021003001020033
53142404114013403
6115231302341223
710313106013536
oct1401103011017
9325410305466
10103231001103
113a86423304a
121800ba2a813
139972013b09
144dd41d931d
152a42c0d453
hex18090c120f

103231001103 has 4 divisors (see below), whose sum is σ = 137641334808. Its totient is φ = 68820667400.

The previous prime is 103231001063. The next prime is 103231001197. The reversal of 103231001103 is 301100132301.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 301100132301 = 3100366710767.

It is a cyclic number.

It is not a de Polignac number, because 103231001103 - 212 = 103230997007 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (103231001303) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17205166848 + ... + 17205166853.

It is an arithmetic number, because the mean of its divisors is an integer number (34410333702).

Almost surely, 2103231001103 is an apocalyptic number.

103231001103 is a deficient number, since it is larger than the sum of its proper divisors (34410333705).

103231001103 is an equidigital number, since it uses as much as digits as its factorization.

103231001103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 34410333704.

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 103231001103 its reverse (301100132301), we get a palindrome (404331133404).

The spelling of 103231001103 in words is "one hundred three billion, two hundred thirty-one million, one thousand, one hundred three".

Divisors: 1 3 34410333701 103231001103