Base | Representation |
---|---|
bin | 11110000010110110001… |
… | …00101101011000101011 |
3 | 10122200121011102020102120 |
4 | 33001123010231120223 |
5 | 113403142422042141 |
6 | 2110124042402323 |
7 | 134403566113215 |
oct | 17013304553053 |
9 | 3580534366376 |
10 | 1032320112171 |
11 | 3688938775a7 |
12 | 1480a1b003a3 |
13 | 7646922827a |
14 | 37d70a775b5 |
15 | 1bcbddd5c66 |
hex | f05b12d62b |
1032320112171 has 4 divisors (see below), whose sum is σ = 1376426816232. Its totient is φ = 688213408112.
The previous prime is 1032320112169. The next prime is 1032320112191. The reversal of 1032320112171 is 1712110232301.
1032320112171 is digitally balanced in base 2 and base 4, because in such bases it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1032320112171 - 21 = 1032320112169 is a prime.
It is not an unprimeable number, because it can be changed into a prime (1032320112191) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 172053352026 + ... + 172053352031.
It is an arithmetic number, because the mean of its divisors is an integer number (344106704058).
Almost surely, 21032320112171 is an apocalyptic number.
1032320112171 is a deficient number, since it is larger than the sum of its proper divisors (344106704061).
1032320112171 is an equidigital number, since it uses as much as digits as its factorization.
1032320112171 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 344106704060.
The product of its (nonzero) digits is 504, while the sum is 24.
Adding to 1032320112171 its reverse (1712110232301), we get a palindrome (2744430344472).
The spelling of 1032320112171 in words is "one trillion, thirty-two billion, three hundred twenty million, one hundred twelve thousand, one hundred seventy-one".
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