Base | Representation |
---|---|
bin | 10111011110001110011000… |
… | …101110010011000111100010 |
3 | 111112111220002122000002120022 |
4 | 113132032120232103013202 |
5 | 102012323320403424442 |
6 | 1003320101141113442 |
7 | 30513162463263311 |
oct | 2736163056230742 |
9 | 445456078002508 |
10 | 103232101233122 |
11 | 2a990540988684 |
12 | b6b30a59b8882 |
13 | 457a98c78a2c4 |
14 | 1b6c663322278 |
15 | be04857be3d2 |
hex | 5de398b931e2 |
103232101233122 has 4 divisors (see below), whose sum is σ = 154848151849686. Its totient is φ = 51616050616560.
The previous prime is 103232101233101. The next prime is 103232101233139. The reversal of 103232101233122 is 221332101232301.
103232101233122 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 97401523146841 + 5830578086281 = 9869221^2 + 2414659^2 .
It is a junction number, because it is equal to n+sod(n) for n = 103232101233091 and 103232101233100.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 25808025308279 + ... + 25808025308282.
Almost surely, 2103232101233122 is an apocalyptic number.
103232101233122 is a deficient number, since it is larger than the sum of its proper divisors (51616050616564).
103232101233122 is an equidigital number, since it uses as much as digits as its factorization.
103232101233122 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 51616050616563.
The product of its (nonzero) digits is 2592, while the sum is 26.
Adding to 103232101233122 its reverse (221332101232301), we get a palindrome (324564202465423).
The spelling of 103232101233122 in words is "one hundred three trillion, two hundred thirty-two billion, one hundred one million, two hundred thirty-three thousand, one hundred twenty-two".
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