Base | Representation |
---|---|
bin | 11110000010110111110… |
… | …10111000011000110011 |
3 | 10122200122011010201022121 |
4 | 33001123322320120303 |
5 | 113403210041004021 |
6 | 2110125311015111 |
7 | 134404130610121 |
oct | 17013372703063 |
9 | 3580564121277 |
10 | 1032334313011 |
11 | 3688a0896931 |
12 | 1480a680a497 |
13 | 7646c15ac31 |
14 | 37d728d2911 |
15 | 1bcc028d741 |
hex | f05beb8633 |
1032334313011 has 4 divisors (see below), whose sum is σ = 1032338609152. Its totient is φ = 1032330016872.
The previous prime is 1032334312969. The next prime is 1032334313027. The reversal of 1032334313011 is 1103134332301.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1032334313011 - 211 = 1032334310963 is a prime.
It is a super-2 number, since 2×10323343130112 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1032334313111) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1764840 + ... + 2275813.
It is an arithmetic number, because the mean of its divisors is an integer number (258084652288).
Almost surely, 21032334313011 is an apocalyptic number.
1032334313011 is a deficient number, since it is larger than the sum of its proper divisors (4296141).
1032334313011 is an equidigital number, since it uses as much as digits as its factorization.
1032334313011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4296140.
The product of its (nonzero) digits is 1944, while the sum is 25.
Adding to 1032334313011 its reverse (1103134332301), we get a palindrome (2135468645312).
The spelling of 1032334313011 in words is "one trillion, thirty-two billion, three hundred thirty-four million, three hundred thirteen thousand, eleven".
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