10324111312013 has 4 divisors (see below), whose sum is σ = 10324294442748. Its totient is φ = 10323928181280.

The previous prime is 10324111312007. The next prime is 10324111312093. The reversal of 10324111312013 is 31021311142301.

10324111312013 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 4921285249609 + 5402826062404 = 2218397^2 + 2324398^2 .

It is a cyclic number.

It is not a de Polignac number, because 10324111312013 - 2³⁶ = 10255391835277 is a prime.

It is a super-2 number, since 2×10324111312013² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 10324111312013.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10324111312003) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 91480778 + ... + 91593563.

It is an arithmetic number, because the mean of its divisors is an integer number (2581073610687).

Almost surely, 2^{10324111312013} is an apocalyptic number.

It is an amenable number.

10324111312013 is a deficient number, since it is larger than the sum of its proper divisors (183130735).

10324111312013 is an equidigital number, since it uses as much as digits as its factorization.

10324111312013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 183130734.

The product of its (nonzero) digits is 432, while the sum is 23.

Adding to 10324111312013 its reverse (31021311142301), we get a palindrome (41345422454314).

The spelling of 10324111312013 in words is "ten trillion, three hundred twenty-four billion, one hundred eleven million, three hundred twelve thousand, thirteen".