10324230433 has 4 divisors (see below), whose sum is σ = 11262796848. Its totient is φ = 9385664020.

The previous prime is 10324230401. The next prime is 10324230457. The reversal of 10324230433 is 33403242301.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 10324230433 - 2⁵ = 10324230401 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10324230398 and 10324230407.

It is not an unprimeable number, because it can be changed into a prime (10324234433) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 469283191 + ... + 469283212.

It is an arithmetic number, because the mean of its divisors is an integer number (2815699212).

Almost surely, 2^10324230433 is an apocalyptic number.

It is an amenable number.

10324230433 is a deficient number, since it is larger than the sum of its proper divisors (938566415).

10324230433 is an equidigital number, since it uses as much as digits as its factorization.

10324230433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 938566414.

The product of its (nonzero) digits is 5184, while the sum is 25.

Adding to 10324230433 its reverse (33403242301), we get a palindrome (43727472734).

The spelling of 10324230433 in words is "ten billion, three hundred twenty-four million, two hundred thirty thousand, four hundred thirty-three".