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103314000433 = 714759142919
BaseRepresentation
bin110000000110111111…
…1101000101000110001
3100212200010112000012111
41200031333220220301
53143041341003213
6115243425325321
710315134341230
oct1401577505061
9325603460174
10103314000433
113a8a7072736
1218033796841
139986284447
145001242b17
152a4a155a3d
hex180dfe8a31

103314000433 has 4 divisors (see below), whose sum is σ = 118073143360. Its totient is φ = 88554857508.

The previous prime is 103314000407. The next prime is 103314000443. The reversal of 103314000433 is 334000413301.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 334000413301 = 2200315179767.

It is a cyclic number.

It is not a de Polignac number, because 103314000433 - 25 = 103314000401 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (103314000443) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7379571453 + ... + 7379571466.

It is an arithmetic number, because the mean of its divisors is an integer number (29518285840).

Almost surely, 2103314000433 is an apocalyptic number.

It is an amenable number.

103314000433 is a deficient number, since it is larger than the sum of its proper divisors (14759142927).

103314000433 is an equidigital number, since it uses as much as digits as its factorization.

103314000433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 14759142926.

The product of its (nonzero) digits is 1296, while the sum is 22.

Adding to 103314000433 its reverse (334000413301), we get a palindrome (437314413734).

The spelling of 103314000433 in words is "one hundred three billion, three hundred fourteen million, four hundred thirty-three", and thus it is an aban number.

Divisors: 1 7 14759142919 103314000433