103331110241113 has 4 divisors (see below), whose sum is σ = 103344178556880. Its totient is φ = 103318041925348.

The previous prime is 103331110241081. The next prime is 103331110241231. The reversal of 103331110241113 is 311142011133301.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 103331110241113 - 2⁵ = 103331110241081 is a prime.

It is a super-2 number, since 2×103331110241113² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (103331110211113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6534146023 + ... + 6534161836.

It is an arithmetic number, because the mean of its divisors is an integer number (25836044639220).

Almost surely, 2^{103331110241113} is an apocalyptic number.

It is an amenable number.

103331110241113 is a deficient number, since it is larger than the sum of its proper divisors (13068315767).

103331110241113 is an equidigital number, since it uses as much as digits as its factorization.

103331110241113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 13068315766.

The product of its (nonzero) digits is 648, while the sum is 25.

Adding to 103331110241113 its reverse (311142011133301), we get a palindrome (414473121374414).

The spelling of 103331110241113 in words is "one hundred three trillion, three hundred thirty-one billion, one hundred ten million, two hundred forty-one thousand, one hundred thirteen".