Base | Representation |
---|---|
bin | 1001011001100001001100… |
… | …1011010011011000001011 |
3 | 1100120220220010200221201120 |
4 | 2112120103023103120023 |
5 | 2323303024314403420 |
6 | 33551214031450323 |
7 | 2114415322361136 |
oct | 226302313233013 |
9 | 40526803627646 |
10 | 10334013044235 |
11 | 33246a2a57931 |
12 | 11aa9740869a3 |
13 | 59c654889cba |
14 | 27a25166721d |
15 | 12dc286cad40 |
hex | 966132d360b |
10334013044235 has 32 divisors (see below), whose sum is σ = 16725745728000. Its totient is φ = 5447739745536.
The previous prime is 10334013044231. The next prime is 10334013044237. The reversal of 10334013044235 is 53244031043301.
It is not a de Polignac number, because 10334013044235 - 22 = 10334013044231 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 10334013044196 and 10334013044205.
It is not an unprimeable number, because it can be changed into a prime (10334013044231) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 2748346 + ... + 5312384.
It is an arithmetic number, because the mean of its divisors is an integer number (522679554000).
Almost surely, 210334013044235 is an apocalyptic number.
10334013044235 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
10334013044235 is a deficient number, since it is larger than the sum of its proper divisors (6391732683765).
10334013044235 is a wasteful number, since it uses less digits than its factorization.
10334013044235 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2567155.
The product of its (nonzero) digits is 51840, while the sum is 33.
Adding to 10334013044235 its reverse (53244031043301), we get a palindrome (63578044087536).
The spelling of 10334013044235 in words is "ten trillion, three hundred thirty-four billion, thirteen million, forty-four thousand, two hundred thirty-five".
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