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103343104113 = 334447701371
BaseRepresentation
bin110000000111110111…
…0101010000001110001
3100212202011021121221120
41200033232222001301
53143121313312423
6115250345212453
710315636614504
oct1401756520161
9325664247846
10103343104113
113a911540767
1218041491129
13998c304462
14500505b13b
152a4c9a3ee3
hex180fbaa071

103343104113 has 4 divisors (see below), whose sum is σ = 137790805488. Its totient is φ = 68895402740.

The previous prime is 103343104087. The next prime is 103343104147. The reversal of 103343104113 is 311401343301.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 103343104113 - 210 = 103343103089 is a prime.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (103343104313) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17223850683 + ... + 17223850688.

It is an arithmetic number, because the mean of its divisors is an integer number (34447701372).

Almost surely, 2103343104113 is an apocalyptic number.

It is an amenable number.

103343104113 is a deficient number, since it is larger than the sum of its proper divisors (34447701375).

103343104113 is an equidigital number, since it uses as much as digits as its factorization.

103343104113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 34447701374.

The product of its (nonzero) digits is 1296, while the sum is 24.

Adding to 103343104113 its reverse (311401343301), we get a palindrome (414744447414).

The spelling of 103343104113 in words is "one hundred three billion, three hundred forty-three million, one hundred four thousand, one hundred thirteen".

Divisors: 1 3 34447701371 103343104113