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103353120143 = 7131135748573
BaseRepresentation
bin110000001000001010…
…0110111010110001111
3100212202212010111100122
41200100110313112033
53143131344321033
6115251344015155
710316121011660
oct1402024672617
9325685114318
10103353120143
113a917161979
12180449014bb
1399914003c0
145006507367
152a4d7d1a98
hex181053758f

103353120143 has 8 divisors (see below), whose sum is σ = 127203840288. Its totient is φ = 81773897184.

The previous prime is 103353120139. The next prime is 103353120173. The reversal of 103353120143 is 341021353301.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 103353120143 - 22 = 103353120139 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (103353120103) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 567874196 + ... + 567874377.

It is an arithmetic number, because the mean of its divisors is an integer number (15900480036).

Almost surely, 2103353120143 is an apocalyptic number.

103353120143 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

103353120143 is a deficient number, since it is larger than the sum of its proper divisors (23850720145).

103353120143 is a wasteful number, since it uses less digits than its factorization.

103353120143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1135748593.

The product of its (nonzero) digits is 3240, while the sum is 26.

Adding to 103353120143 its reverse (341021353301), we get a palindrome (444374473444).

The spelling of 103353120143 in words is "one hundred three billion, three hundred fifty-three million, one hundred twenty thousand, one hundred forty-three".

Divisors: 1 7 13 91 1135748573 7950240011 14764731449 103353120143