1034113114113 has 4 divisors (see below), whose sum is σ = 1378817485488. Its totient is φ = 689408742740.

The previous prime is 1034113114091. The next prime is 1034113114117. The reversal of 1034113114113 is 3114113114301.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1034113114113 - 2³² = 1029818146817 is a prime.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (1034113114117) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 172352185683 + ... + 172352185688.

It is an arithmetic number, because the mean of its divisors is an integer number (344704371372).

Almost surely, 2^{1034113114113} is an apocalyptic number.

It is an amenable number.

1034113114113 is a deficient number, since it is larger than the sum of its proper divisors (344704371375).

1034113114113 is an equidigital number, since it uses as much as digits as its factorization.

1034113114113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 344704371374.

The product of its (nonzero) digits is 432, while the sum is 24.

Adding to 1034113114113 its reverse (3114113114301), we get a palindrome (4148226228414).

The spelling of 1034113114113 in words is "one trillion, thirty-four billion, one hundred thirteen million, one hundred fourteen thousand, one hundred thirteen".