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10341132203143 = 72515885675699
BaseRepresentation
bin1001011001111011101110…
…0000101111010010000111
31100121121021021122200210201
42112132323200233102013
52323412114321000033
633554352304031331
72115056616256360
oct226367340572207
940547237580721
1010341132203143
113327716599335
1211b0220302547
135a021a784071
1427a728d60b67
1512dee36d147d
hex967bb82f487

10341132203143 has 8 divisors (see below), whose sum is σ = 11865522211200. Its totient is φ = 8828513547000.

The previous prime is 10341132203141. The next prime is 10341132203159. The reversal of 10341132203143 is 34130223114301.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 10341132203143 - 21 = 10341132203141 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10341132203141) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2942836093 + ... + 2942839606.

It is an arithmetic number, because the mean of its divisors is an integer number (1483190276400).

Almost surely, 210341132203143 is an apocalyptic number.

10341132203143 is a deficient number, since it is larger than the sum of its proper divisors (1524390008057).

10341132203143 is an equidigital number, since it uses as much as digits as its factorization.

10341132203143 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5885675957.

The product of its (nonzero) digits is 5184, while the sum is 28.

Adding to 10341132203143 its reverse (34130223114301), we get a palindrome (44471355317444).

The spelling of 10341132203143 in words is "ten trillion, three hundred forty-one billion, one hundred thirty-two million, two hundred three thousand, one hundred forty-three".

Divisors: 1 7 251 1757 5885675699 41199729893 1477304600449 10341132203143