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103412051455 = 525182400041
BaseRepresentation
bin110000001001111010…
…1101010110111111111
3100212220222000111220211
41200103311222313333
53143241441121310
6115301251053251
710320434635246
oct1402365526777
9325828014824
10103412051455
113a947452939
12180605a1227
1399a0694abb
14501028795d
152a53a72c8a
hex1813d6adff

103412051455 has 8 divisors (see below), whose sum is σ = 124588863504. Its totient is φ = 82400040000.

The previous prime is 103412051441. The next prime is 103412051471. The reversal of 103412051455 is 554150214301.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 103412051455 - 221 = 103409954303 is a prime.

It is a super-2 number, since 2×1034120514552 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 41198766 + ... + 41201275.

It is an arithmetic number, because the mean of its divisors is an integer number (15573607938).

Almost surely, 2103412051455 is an apocalyptic number.

103412051455 is a deficient number, since it is larger than the sum of its proper divisors (21176812049).

103412051455 is an equidigital number, since it uses as much as digits as its factorization.

103412051455 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 82400297.

The product of its (nonzero) digits is 12000, while the sum is 31.

Adding to 103412051455 its reverse (554150214301), we get a palindrome (657562265756).

The spelling of 103412051455 in words is "one hundred three billion, four hundred twelve million, fifty-one thousand, four hundred fifty-five".

Divisors: 1 5 251 1255 82400041 412000205 20682410291 103412051455