Base | Representation |
---|---|
bin | 11110000110100011111… |
… | …00000001000001111010 |
3 | 10122212202010212121002102 |
4 | 33003101330001001322 |
5 | 113421233431301132 |
6 | 2111054001303402 |
7 | 134504162451161 |
oct | 17032174010172 |
9 | 3585663777072 |
10 | 1034314322042 |
11 | 369717519a31 |
12 | 148559934b62 |
13 | 766c6426001 |
14 | 380bd8663d8 |
15 | 1bd89002c62 |
hex | f0d1f0107a |
1034314322042 has 4 divisors (see below), whose sum is σ = 1551471483066. Its totient is φ = 517157161020.
The previous prime is 1034314322023. The next prime is 1034314322047. The reversal of 1034314322042 is 2402234134301.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 674075482441 + 360238839601 = 821021^2 + 600199^2 .
It is a super-2 number, since 2×10343143220422 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1034314321996 and 1034314322014.
It is not an unprimeable number, because it can be changed into a prime (1034314322047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 258578580509 + ... + 258578580512.
Almost surely, 21034314322042 is an apocalyptic number.
1034314322042 is a deficient number, since it is larger than the sum of its proper divisors (517157161024).
1034314322042 is an equidigital number, since it uses as much as digits as its factorization.
1034314322042 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 517157161023.
The product of its (nonzero) digits is 13824, while the sum is 29.
Adding to 1034314322042 its reverse (2402234134301), we get a palindrome (3436548456343).
The spelling of 1034314322042 in words is "one trillion, thirty-four billion, three hundred fourteen million, three hundred twenty-two thousand, forty-two".
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