Base | Representation |
---|---|
bin | 110000001010100011… |
… | …0001000110000111101 |
3 | 100212222102201012101020 |
4 | 1200111012020300331 |
5 | 3143312341123110 |
6 | 115303323134353 |
7 | 10321112141532 |
oct | 1402506106075 |
9 | 325872635336 |
10 | 103433145405 |
11 | 3a958350057 |
12 | 180676743b9 |
13 | 99a4b6c125 |
14 | 5012db8d89 |
15 | 2a5583cd70 |
hex | 1815188c3d |
103433145405 has 8 divisors (see below), whose sum is σ = 165493032672. Its totient is φ = 55164344208.
The previous prime is 103433145401. The next prime is 103433145427. The reversal of 103433145405 is 504541334301.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 103433145405 - 22 = 103433145401 is a prime.
It is a super-2 number, since 2×1034331454052 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (103433145401) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3447771499 + ... + 3447771528.
It is an arithmetic number, because the mean of its divisors is an integer number (20686629084).
Almost surely, 2103433145405 is an apocalyptic number.
103433145405 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
103433145405 is a deficient number, since it is larger than the sum of its proper divisors (62059887267).
103433145405 is an equidigital number, since it uses as much as digits as its factorization.
103433145405 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6895543035.
The product of its (nonzero) digits is 43200, while the sum is 33.
Adding to 103433145405 its reverse (504541334301), we get a palindrome (607974479706).
The spelling of 103433145405 in words is "one hundred three billion, four hundred thirty-three million, one hundred forty-five thousand, four hundred five".
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