103434213433 has 4 divisors (see below), whose sum is σ = 103460529808. Its totient is φ = 103407897060.

The previous prime is 103434213401. The next prime is 103434213437. The reversal of 103434213433 is 334312434301.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 103434213433 - 2⁵ = 103434213401 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 103434213395 and 103434213404.

It is not an unprimeable number, because it can be changed into a prime (103434213437) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13152291 + ... + 13160152.

It is an arithmetic number, because the mean of its divisors is an integer number (25865132452).

Almost surely, 2^103434213433 is an apocalyptic number.

It is an amenable number.

103434213433 is a deficient number, since it is larger than the sum of its proper divisors (26316375).

103434213433 is an equidigital number, since it uses as much as digits as its factorization.

103434213433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 26316374.

The product of its (nonzero) digits is 31104, while the sum is 31.

Adding to 103434213433 its reverse (334312434301), we get a palindrome (437746647734).

The spelling of 103434213433 in words is "one hundred three billion, four hundred thirty-four million, two hundred thirteen thousand, four hundred thirty-three".