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103434213437 is a prime number
BaseRepresentation
bin110000001010100101…
…0001101100000111101
3100212222111201110102222
41200111022031200331
53143313124312222
6115303402055125
710321124210402
oct1402512154075
9325874643388
10103434213437
113a958a0a525
1218067aaa4a5
1399a51542b9
1450131b62a9
152a5599e542
hex181528d83d

103434213437 has 2 divisors, whose sum is σ = 103434213438. Its totient is φ = 103434213436.

The previous prime is 103434213401. The next prime is 103434213497. The reversal of 103434213437 is 734312434301.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 95786536036 + 7647677401 = 309494^2 + 87451^2 .

It is a cyclic number.

It is not a de Polignac number, because 103434213437 - 218 = 103433951293 is a prime.

It is a super-3 number, since 3×1034342134373 (a number of 34 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 103434213397 and 103434213406.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (103434213497) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 51717106718 + 51717106719.

It is an arithmetic number, because the mean of its divisors is an integer number (51717106719).

Almost surely, 2103434213437 is an apocalyptic number.

It is an amenable number.

103434213437 is a deficient number, since it is larger than the sum of its proper divisors (1).

103434213437 is an equidigital number, since it uses as much as digits as its factorization.

103434213437 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 72576, while the sum is 35.

Adding to 103434213437 its reverse (734312434301), we get a palindrome (837746647738).

The spelling of 103434213437 in words is "one hundred three billion, four hundred thirty-four million, two hundred thirteen thousand, four hundred thirty-seven".