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10344314111 = 23943281649
BaseRepresentation
bin10011010001001000…
…11011010011111111
3222200220122121021212
421220210123103333
5132141121022421
64430242315035
7514225135115
oct115044332377
928626577255
1010344314111
11442910632a
122008358a7b
13c8b132631
14701b8dab5
15408221e5b
hex26891b4ff

10344314111 has 4 divisors (see below), whose sum is σ = 10387596000. Its totient is φ = 10301032224.

The previous prime is 10344314089. The next prime is 10344314119. The reversal of 10344314111 is 11141344301.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 11141344301 = 40127783901.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-10344314111 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10344314119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21640586 + ... + 21641063.

It is an arithmetic number, because the mean of its divisors is an integer number (2596899000).

Almost surely, 210344314111 is an apocalyptic number.

10344314111 is a deficient number, since it is larger than the sum of its proper divisors (43281889).

10344314111 is an equidigital number, since it uses as much as digits as its factorization.

10344314111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 43281888.

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 10344314111 its reverse (11141344301), we get a palindrome (21485658412).

The spelling of 10344314111 in words is "ten billion, three hundred forty-four million, three hundred fourteen thousand, one hundred eleven".

Divisors: 1 239 43281649 10344314111