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103444121433 = 33110910204609
BaseRepresentation
bin110000001010111000…
…0000000011101011001
3100220000012100211122210
41200111300000131121
53143323143341213
6115304354305333
710321304344602
oct1402560003531
9326005324583
10103444121433
113a963567554
121806b288249
1399a7213013
145014634da9
152a567aa0c3
hex1815c00759

103444121433 has 16 divisors (see below), whose sum is σ = 143680908800. Its totient is φ = 66125859840.

The previous prime is 103444121419. The next prime is 103444121453. The reversal of 103444121433 is 334121444301.

It is not a de Polignac number, because 103444121433 - 28 = 103444121177 is a prime.

It is a super-3 number, since 3×1034441214333 (a number of 34 digits) contains 333 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 103444121433.

It is not an unprimeable number, because it can be changed into a prime (103444121453) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 5092168 + ... + 5112441.

It is an arithmetic number, because the mean of its divisors is an integer number (8980056800).

Almost surely, 2103444121433 is an apocalyptic number.

It is an amenable number.

103444121433 is a deficient number, since it is larger than the sum of its proper divisors (40236787367).

103444121433 is a wasteful number, since it uses less digits than its factorization.

103444121433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10204752.

The product of its (nonzero) digits is 13824, while the sum is 30.

Adding to 103444121433 its reverse (334121444301), we get a palindrome (437565565734).

The spelling of 103444121433 in words is "one hundred three billion, four hundred forty-four million, one hundred twenty-one thousand, four hundred thirty-three".

Divisors: 1 3 31 93 109 327 3379 10137 10204609 30613827 316342879 949028637 1112302381 3336907143 34481373811 103444121433