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10352040463 = 70687146449
BaseRepresentation
bin10011010010000011…
…11001101000001111
3222201110012010212001
421221001321220033
5132200110243323
64431120053131
7514350614662
oct115101715017
928643163761
1010352040463
114432503246
12200aa641a7
13c8c90933b
14702c016d9
15408c4b3ad
hex269079a0f

10352040463 has 4 divisors (see below), whose sum is σ = 10352257600. Its totient is φ = 10351823328.

The previous prime is 10352040437. The next prime is 10352040481. The reversal of 10352040463 is 36404025301.

10352040463 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-10352040463 is a prime.

It is a super-3 number, since 3×103520404633 (a number of 31 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10352040403) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2538 + ... + 143911.

It is an arithmetic number, because the mean of its divisors is an integer number (2588064400).

Almost surely, 210352040463 is an apocalyptic number.

10352040463 is a deficient number, since it is larger than the sum of its proper divisors (217137).

10352040463 is an equidigital number, since it uses as much as digits as its factorization.

10352040463 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 217136.

The product of its (nonzero) digits is 8640, while the sum is 28.

Adding to 10352040463 its reverse (36404025301), we get a palindrome (46756065764).

The spelling of 10352040463 in words is "ten billion, three hundred fifty-two million, forty thousand, four hundred sixty-three".

Divisors: 1 70687 146449 10352040463