Base | Representation |
---|---|
bin | 11110001000001110101… |
… | …00110011011101011001 |
3 | 10122222001120021101102021 |
4 | 33010013110303131121 |
5 | 113430102230400010 |
6 | 2111322515134441 |
7 | 134535316630504 |
oct | 17040724633531 |
9 | 3588046241367 |
10 | 1035210012505 |
11 | 36a037078489 |
12 | 1487698a4421 |
13 | 76809b70c76 |
14 | 381667c013b |
15 | 1bddc97c8da |
hex | f107533759 |
1035210012505 has 4 divisors (see below), whose sum is σ = 1242252015012. Its totient is φ = 828168010000.
The previous prime is 1035210012493. The next prime is 1035210012521. The reversal of 1035210012505 is 5052100125301.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 162160846864 + 873049165641 = 402692^2 + 934371^2 .
It is not a de Polignac number, because 1035210012505 - 29 = 1035210011993 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 1035210012505.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 103521001246 + ... + 103521001255.
It is an arithmetic number, because the mean of its divisors is an integer number (310563003753).
Almost surely, 21035210012505 is an apocalyptic number.
It is an amenable number.
1035210012505 is a deficient number, since it is larger than the sum of its proper divisors (207042002507).
1035210012505 is an equidigital number, since it uses as much as digits as its factorization.
1035210012505 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 207042002506.
The product of its (nonzero) digits is 1500, while the sum is 25.
Adding to 1035210012505 its reverse (5052100125301), we get a palindrome (6087310137806).
The spelling of 1035210012505 in words is "one trillion, thirty-five billion, two hundred ten million, twelve thousand, five hundred five".
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