Base | Representation |
---|---|
bin | 1001011010110000001111… |
… | …1111000011100110010001 |
3 | 1100122221122222211000021210 |
4 | 2112230003333003212101 |
5 | 2324130004122341423 |
6 | 34005043421210333 |
7 | 2116066220206533 |
oct | 226540377034621 |
9 | 40587588730253 |
10 | 10355233012113 |
11 | 33326a2090870 |
12 | 11b2ab67009a9 |
13 | 5a1656c2aa02 |
14 | 27b2a5999853 |
15 | 12e56b5c8b93 |
hex | 96b03fc3991 |
10355233012113 has 16 divisors (see below), whose sum is σ = 15087816688896. Its totient is φ = 6265207303440.
The previous prime is 10355233012087. The next prime is 10355233012129. The reversal of 10355233012113 is 31121033255301.
10355233012113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 10355233012113 - 28 = 10355233011857 is a prime.
It is a super-3 number, since 3×103552330121133 (a number of 40 digits) contains 333 as substring.
It is not an unprimeable number, because it can be changed into a prime (10355233012013) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 267267631 + ... + 267306372.
It is an arithmetic number, because the mean of its divisors is an integer number (942988543056).
Almost surely, 210355233012113 is an apocalyptic number.
It is an amenable number.
10355233012113 is a deficient number, since it is larger than the sum of its proper divisors (4732583676783).
10355233012113 is a wasteful number, since it uses less digits than its factorization.
10355233012113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 534574604.
The product of its (nonzero) digits is 8100, while the sum is 30.
Adding to 10355233012113 its reverse (31121033255301), we get a palindrome (41476266267414).
The spelling of 10355233012113 in words is "ten trillion, three hundred fifty-five billion, two hundred thirty-three million, twelve thousand, one hundred thirteen".
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