Base | Representation |
---|---|
bin | 110000001110001001… |
… | …1100011011101011111 |
3 | 100220021212022111012011 |
4 | 1200130103203131133 |
5 | 3144034322300020 |
6 | 115323323452051 |
7 | 10324111232140 |
oct | 1403423433537 |
9 | 326255274164 |
10 | 103554103135 |
11 | 3aa0a65641a |
12 | 180a0087027 |
13 | 99c3c3cc52 |
14 | 50250a3ac7 |
15 | 2a6128235a |
hex | 181c4e375f |
103554103135 has 8 divisors (see below), whose sum is σ = 142017055776. Its totient is φ = 71008527840.
The previous prime is 103554103129. The next prime is 103554103181. The reversal of 103554103135 is 531301455301.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 103554103135 - 27 = 103554103007 is a prime.
It is a super-3 number, since 3×1035541031353 (a number of 34 digits) contains 333 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 103554103097 and 103554103106.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1479344296 + ... + 1479344365.
It is an arithmetic number, because the mean of its divisors is an integer number (17752131972).
Almost surely, 2103554103135 is an apocalyptic number.
103554103135 is a deficient number, since it is larger than the sum of its proper divisors (38462952641).
103554103135 is an equidigital number, since it uses as much as digits as its factorization.
103554103135 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2958688673.
The product of its (nonzero) digits is 13500, while the sum is 31.
Adding to 103554103135 its reverse (531301455301), we get a palindrome (634855558436).
The spelling of 103554103135 in words is "one hundred three billion, five hundred fifty-four million, one hundred three thousand, one hundred thirty-five".
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