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10355513001 = 311087311341
BaseRepresentation
bin10011010010011110…
…01001011010101001
3222201200201120021120
421221033021122221
5132202002404001
64431322325453
7514422260001
oct115117113251
928650646246
1010355513001
114434465209
122010059889
13c90553ab2
14703467001
154091d5236
hex2693c96a9

10355513001 has 8 divisors (see below), whose sum is σ = 13808640384. Its totient is φ = 6903030480.

The previous prime is 10355512919. The next prime is 10355513023. The reversal of 10355513001 is 10031555301.

10355513001 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 10355513001 - 27 = 10355512873 is a prime.

It is a super-3 number, since 3×103555130013 (a number of 31 digits) contains 333 as substring.

It is not an unprimeable number, because it can be changed into a prime (10355513081) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 122410 + ... + 188931.

It is an arithmetic number, because the mean of its divisors is an integer number (1726080048).

Almost surely, 210355513001 is an apocalyptic number.

It is an amenable number.

10355513001 is a deficient number, since it is larger than the sum of its proper divisors (3453127383).

10355513001 is a wasteful number, since it uses less digits than its factorization.

10355513001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 322431.

The product of its (nonzero) digits is 1125, while the sum is 24.

The spelling of 10355513001 in words is "ten billion, three hundred fifty-five million, five hundred thirteen thousand, one".

Divisors: 1 3 11087 33261 311341 934023 3451837667 10355513001