Base | Representation |
---|---|
bin | 110000001110001011… |
… | …1110111000101101011 |
3 | 100220021221102211211221 |
4 | 1200130113313011223 |
5 | 3144040114411412 |
6 | 115323404002511 |
7 | 10324123643455 |
oct | 1403427670553 |
9 | 326257384757 |
10 | 103555232107 |
11 | 3aa10257658 |
12 | 180a0530437 |
13 | 99c4246a92 |
14 | 50252b92d5 |
15 | 2a61406b07 |
hex | 181c5f716b |
103555232107 has 4 divisors (see below), whose sum is σ = 103623767856. Its totient is φ = 103486696360.
The previous prime is 103555232071. The next prime is 103555232119. The reversal of 103555232107 is 701232555301.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 103555232107 - 27 = 103555231979 is a prime.
It is a super-3 number, since 3×1035552321073 (a number of 34 digits) contains 333 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (103555232167) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 34265608 + ... + 34268629.
It is an arithmetic number, because the mean of its divisors is an integer number (25905941964).
Almost surely, 2103555232107 is an apocalyptic number.
103555232107 is a deficient number, since it is larger than the sum of its proper divisors (68535749).
103555232107 is an equidigital number, since it uses as much as digits as its factorization.
103555232107 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 68535748.
The product of its (nonzero) digits is 31500, while the sum is 34.
Adding to 103555232107 its reverse (701232555301), we get a palindrome (804787787408).
The spelling of 103555232107 in words is "one hundred three billion, five hundred fifty-five million, two hundred thirty-two thousand, one hundred seven".
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