1038431245 has 4 divisors (see below), whose sum is σ = 1246117500. Its totient is φ = 830744992.

The previous prime is 1038431237. The next prime is 1038431267. The reversal of 1038431245 is 5421348301.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 5421348301 = 28771 ⋅188431.

It can be written as a sum of positive squares in 2 ways, for example, as 557857161 + 480574084 = 23619^2 + 21922^2 .

It is a cyclic number.

It is not a de Polignac number, because 1038431245 - 2³ = 1038431237 is a prime.

It is a super-3 number, since 3×1038431245³ (a number of 28 digits) contains 333 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 103843120 + ... + 103843129.

It is an arithmetic number, because the mean of its divisors is an integer number (311529375).

Almost surely, 2^1038431245 is an apocalyptic number.

It is an amenable number.

1038431245 is a deficient number, since it is larger than the sum of its proper divisors (207686255).

1038431245 is an equidigital number, since it uses as much as digits as its factorization.

1038431245 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 207686254.

The product of its (nonzero) digits is 11520, while the sum is 31.

The square root of 1038431245 is about 32224.6993003814. The cubic root of 1038431245 is about 1012.6497247463.

Adding to 1038431245 its reverse (5421348301), we get a palindrome (6459779546).

It can be divided in two parts, 103 and 8431245, that added together give a palindrome (8431348).

The spelling of 1038431245 in words is "one billion, thirty-eight million, four hundred thirty-one thousand, two hundred forty-five".