Base | Representation |
---|---|
bin | 10111101001011011100010… |
… | …001000100100001001111010 |
3 | 111122020111200101202010022202 |
4 | 113221123202020210021322 |
5 | 102112432331243021102 |
6 | 1005105530404550202 |
7 | 30622622532645035 |
oct | 2751334210441172 |
9 | 448214611663282 |
10 | 104002132001402 |
11 | 30158069203a78 |
12 | b7b83876b2362 |
13 | 460548885546b |
14 | 1b97a3136c01c |
15 | c05502a13e02 |
hex | 5e96e222427a |
104002132001402 has 4 divisors (see below), whose sum is σ = 156003198002106. Its totient is φ = 52001066000700.
The previous prime is 104002132001401. The next prime is 104002132001459. The reversal of 104002132001402 is 204100231200401.
104002132001402 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 53049503353081 + 50952628648321 = 7283509^2 + 7138111^2 .
It is not an unprimeable number, because it can be changed into a prime (104002132001401) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26000533000349 + ... + 26000533000352.
Almost surely, 2104002132001402 is an apocalyptic number.
104002132001402 is a deficient number, since it is larger than the sum of its proper divisors (52001066000704).
104002132001402 is an equidigital number, since it uses as much as digits as its factorization.
104002132001402 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 52001066000703.
The product of its (nonzero) digits is 384, while the sum is 20.
Adding to 104002132001402 its reverse (204100231200401), we get a palindrome (308102363201803).
The spelling of 104002132001402 in words is "one hundred four trillion, two billion, one hundred thirty-two million, one thousand, four hundred two".
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