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104011003143 = 3220695585683
BaseRepresentation
bin110000011011110001…
…0011111010100000111
3100221110201001102011200
41200313202133110013
53201003304100033
6115440524433543
710341326640135
oct1406742372407
9327421042150
10104011003143
1140124555133
12181a90a88b3
139a677b4498
145069a3a755
152a8b435013
hex183789f507

104011003143 has 12 divisors (see below), whose sum is σ = 150310756440. Its totient is φ = 69307142256.

The previous prime is 104011003133. The next prime is 104011003147. The reversal of 104011003143 is 341300110401.

It is not a de Polignac number, because 104011003143 - 24 = 104011003127 is a prime.

It is a super-3 number, since 3×1040110031433 (a number of 34 digits) contains 333 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (104011003147) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 2774221 + ... + 2811462.

It is an arithmetic number, because the mean of its divisors is an integer number (12525896370).

Almost surely, 2104011003143 is an apocalyptic number.

104011003143 is a deficient number, since it is larger than the sum of its proper divisors (46299753297).

104011003143 is a wasteful number, since it uses less digits than its factorization.

104011003143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5587758 (or 5587755 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 18.

Adding to 104011003143 its reverse (341300110401), we get a palindrome (445311113544).

The spelling of 104011003143 in words is "one hundred four billion, eleven million, three thousand, one hundred forty-three".

Divisors: 1 3 9 2069 6207 18621 5585683 16757049 50271147 11556778127 34670334381 104011003143