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10401300343 = 71559953111
BaseRepresentation
bin10011010111111011…
…10011111101110111
3222211212212210201001
421223331303331313
5132300213102333
64440035544131
7515516410540
oct115375637567
928755783631
1010401300343
114458298995
12202345b047
13c99b958b5
147095854c7
1540d22bb7d
hex26bf73f77

10401300343 has 8 divisors (see below), whose sum is σ = 11894837760. Its totient is φ = 8909672280.

The previous prime is 10401300337. The next prime is 10401300367. The reversal of 10401300343 is 34300310401.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-10401300343 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 10401300343.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (10401300323) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 465643 + ... + 487468.

It is an arithmetic number, because the mean of its divisors is an integer number (1486854720).

Almost surely, 210401300343 is an apocalyptic number.

10401300343 is a deficient number, since it is larger than the sum of its proper divisors (1493537417).

10401300343 is an equidigital number, since it uses as much as digits as its factorization.

10401300343 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 954677.

The product of its (nonzero) digits is 432, while the sum is 19.

Adding to 10401300343 its reverse (34300310401), we get a palindrome (44701610744).

The spelling of 10401300343 in words is "ten billion, four hundred one million, three hundred thousand, three hundred forty-three".

Divisors: 1 7 1559 10913 953111 6671777 1485900049 10401300343