104013224111 has 4 divisors (see below), whose sum is σ = 104188626432. Its totient is φ = 103837821792.

The previous prime is 104013224101. The next prime is 104013224113. The reversal of 104013224111 is 111422310401.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 111422310401 = 17 ⋅6554253553.

It is a cyclic number.

It is not a de Polignac number, because 104013224111 - 2¹⁸ = 104012961967 is a prime.

It is a super-2 number, since 2×104013224111² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (104013224113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 87700271 + ... + 87701456.

It is an arithmetic number, because the mean of its divisors is an integer number (26047156608).

Almost surely, 2^104013224111 is an apocalyptic number.

104013224111 is a deficient number, since it is larger than the sum of its proper divisors (175402321).

104013224111 is an equidigital number, since it uses as much as digits as its factorization.

104013224111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 175402320.

The product of its (nonzero) digits is 192, while the sum is 20.

Adding to 104013224111 its reverse (111422310401), we get a palindrome (215435534512).

The spelling of 104013224111 in words is "one hundred four billion, thirteen million, two hundred twenty-four thousand, one hundred eleven".