Base | Representation |
---|---|
bin | 1001011101100010111110… |
… | …1001101000100100000001 |
3 | 1100211112111121102102010221 |
4 | 2113120233221220210001 |
5 | 2330421233304442423 |
6 | 34043100243423041 |
7 | 2122415150651404 |
oct | 227305751504401 |
9 | 40745447372127 |
10 | 10403210234113 |
11 | 3350a81a69864 |
12 | 1200266084a81 |
13 | 5a60318a9678 |
14 | 27d7377c1d3b |
15 | 1309285abe5d |
hex | 9762fa68901 |
10403210234113 has 8 divisors (see below), whose sum is σ = 10566127656320. Its totient is φ = 10240517683440.
The previous prime is 10403210234099. The next prime is 10403210234161. The reversal of 10403210234113 is 31143201230401.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 10403210234113 - 213 = 10403210225921 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (10403210234173) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 56124633 + ... + 56309686.
It is an arithmetic number, because the mean of its divisors is an integer number (1320765957040).
Almost surely, 210403210234113 is an apocalyptic number.
It is an amenable number.
10403210234113 is a deficient number, since it is larger than the sum of its proper divisors (162917422207).
10403210234113 is a wasteful number, since it uses less digits than its factorization.
10403210234113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 112435767.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 10403210234113 its reverse (31143201230401), we get a palindrome (41546411464514).
The spelling of 10403210234113 in words is "ten trillion, four hundred three billion, two hundred ten million, two hundred thirty-four thousand, one hundred thirteen".
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