104032113 has 4 divisors (see below), whose sum is σ = 138709488. Its totient is φ = 69354740.

The previous prime is 104032069. The next prime is 104032157. The reversal of 104032113 is 311230401.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 311230401 = 3 ⋅103743467.

It is an interprime number because it is at equal distance from previous prime (104032069) and next prime (104032157).

It is a cyclic number.

It is not a de Polignac number, because 104032113 - 2²¹ = 101934961 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 104032092 and 104032101.

It is not an unprimeable number, because it can be changed into a prime (104032213) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17338683 + ... + 17338688.

It is an arithmetic number, because the mean of its divisors is an integer number (34677372).

Almost surely, 2^104032113 is an apocalyptic number.

It is an amenable number.

104032113 is a deficient number, since it is larger than the sum of its proper divisors (34677375).

104032113 is an equidigital number, since it uses as much as digits as its factorization.

104032113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 34677374.

The product of its (nonzero) digits is 72, while the sum is 15.

The square root of 104032113 is about 10199.6133750255. The cubic root of 104032113 is about 470.3153353905.

Adding to 104032113 its reverse (311230401), we get a palindrome (415262514).

It can be divided in two parts, 1040 and 32113, that added together give a triangular number (33153 = T₂₅₇).

The spelling of 104032113 in words is "one hundred four million, thirty-two thousand, one hundred thirteen".