Base | Representation |
---|---|
bin | 10011011000010010… |
… | …11000001100000101 |
3 | 222212002120211202111 |
4 | 21230021120030011 |
5 | 132302002113133 |
6 | 4440224541021 |
7 | 515554236205 |
oct | 115411301405 |
9 | 28762524674 |
10 | 10404332293 |
11 | 4459a79933 |
12 | 2024481771 |
13 | c9a6b7954 |
14 | 709b34405 |
15 | 40d62a1cd |
hex | 26c258305 |
10404332293 has 4 divisors (see below), whose sum is σ = 10433314080. Its totient is φ = 10375350508.
The previous prime is 10404332209. The next prime is 10404332317. The reversal of 10404332293 is 39223340401.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 10404332293 - 217 = 10404201221 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (10404332593) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14490355 + ... + 14491072.
It is an arithmetic number, because the mean of its divisors is an integer number (2608328520).
Almost surely, 210404332293 is an apocalyptic number.
It is an amenable number.
10404332293 is a deficient number, since it is larger than the sum of its proper divisors (28981787).
10404332293 is an equidigital number, since it uses as much as digits as its factorization.
10404332293 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 28981786.
The product of its (nonzero) digits is 15552, while the sum is 31.
Adding to 10404332293 its reverse (39223340401), we get a palindrome (49627672694).
The spelling of 10404332293 in words is "ten billion, four hundred four million, three hundred thirty-two thousand, two hundred ninety-three".
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