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10405113 = 329199601
BaseRepresentation
bin100111101100…
…010011111001
3201120122010120
4213230103321
510130430423
61011003453
7154304415
oct47542371
921518116
1010405113
115967574
123599589
132204094
14154bd45
15da7ee3
hex9ec4f9

10405113 has 16 divisors (see below), whose sum is σ = 14448000. Its totient is φ = 6652800.

The previous prime is 10405111. The next prime is 10405133. The reversal of 10405113 is 31150401.

10405113 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 10405113 - 21 = 10405111 is a prime.

It is a super-3 number, since 3×104051133 (a number of 22 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 10405092 and 10405101.

It is not an unprimeable number, because it can be changed into a prime (10405111) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 17013 + ... + 17613.

It is an arithmetic number, because the mean of its divisors is an integer number (903000).

Almost surely, 210405113 is an apocalyptic number.

It is an amenable number.

10405113 is a deficient number, since it is larger than the sum of its proper divisors (4042887).

10405113 is a wasteful number, since it uses less digits than its factorization.

10405113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 832.

The product of its (nonzero) digits is 60, while the sum is 15.

The square root of 10405113 is about 3225.6957389066. The cubic root of 10405113 is about 218.3143418531.

Adding to 10405113 its reverse (31150401), we get a palindrome (41555514).

The spelling of 10405113 in words is "ten million, four hundred five thousand, one hundred thirteen".

Divisors: 1 3 29 87 199 597 601 1803 5771 17313 17429 52287 119599 358797 3468371 10405113