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1041013161433 = 74123771525967
BaseRepresentation
bin11110010011000010011…
…10000011110111011001
310200112000222220220012001
433021201032003313121
5114023443332131213
62114122420521001
7135132163605160
oct17114116036731
93615028826161
101041013161433
11371544877133
12149909250161
1377223215abb
14385573ca3d7
151c12c17e1dd
hexf261383dd9

1041013161433 has 16 divisors (see below), whose sum is σ = 1219260639744. Its totient is φ = 870166851840.

The previous prime is 1041013161427. The next prime is 1041013161499. The reversal of 1041013161433 is 3341613101401.

It is a happy number.

It is a cyclic number.

It is not a de Polignac number, because 1041013161433 - 213 = 1041013153241 is a prime.

It is a super-2 number, since 2×10410131614332 (a number of 25 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (1041013162433) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 80785 + ... + 1445182.

It is an arithmetic number, because the mean of its divisors is an integer number (76203789984).

Almost surely, 21041013161433 is an apocalyptic number.

It is an amenable number.

1041013161433 is a deficient number, since it is larger than the sum of its proper divisors (178247478311).

1041013161433 is a wasteful number, since it uses less digits than its factorization.

1041013161433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1528392.

The product of its (nonzero) digits is 2592, while the sum is 28.

Adding to 1041013161433 its reverse (3341613101401), we get a palindrome (4382626262834).

The spelling of 1041013161433 in words is "one trillion, forty-one billion, thirteen million, one hundred sixty-one thousand, four hundred thirty-three".

Divisors: 1 7 41 287 2377 16639 97457 682199 1525967 10681769 62564647 437952529 3627223559 25390564913 148716165919 1041013161433