104115551433 has 4 divisors (see below), whose sum is σ = 138820735248. Its totient is φ = 69410367620.

The previous prime is 104115551431. The next prime is 104115551443. The reversal of 104115551433 is 334155511401.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 104115551433 - 2¹ = 104115551431 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 104115551394 and 104115551403.

It is not an unprimeable number, because it can be changed into a prime (104115551431) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17352591903 + ... + 17352591908.

It is an arithmetic number, because the mean of its divisors is an integer number (34705183812).

Almost surely, 2^104115551433 is an apocalyptic number.

It is an amenable number.

104115551433 is a deficient number, since it is larger than the sum of its proper divisors (34705183815).

104115551433 is an equidigital number, since it uses as much as digits as its factorization.

104115551433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 34705183814.

The product of its (nonzero) digits is 18000, while the sum is 33.

The spelling of 104115551433 in words is "one hundred four billion, one hundred fifteen million, five hundred fifty-one thousand, four hundred thirty-three".