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10412223433 = 43242144731
BaseRepresentation
bin10011011001001110…
…11110101111001001
3222212122102202100221
421230213132233021
5132311012122213
64441110030041
7516011303353
oct115447365711
928778382327
1010412223433
114463479637
122027048321
13c9c21b671
1470abca0d3
1540e18838d
hex26c9debc9

10412223433 has 4 divisors (see below), whose sum is σ = 10654368208. Its totient is φ = 10170078660.

The previous prime is 10412223403. The next prime is 10412223439. The reversal of 10412223433 is 33432221401.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 10412223433 - 225 = 10378669001 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 10412223398 and 10412223407.

It is not an unprimeable number, because it can be changed into a prime (10412223439) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 121072323 + ... + 121072408.

It is an arithmetic number, because the mean of its divisors is an integer number (2663592052).

Almost surely, 210412223433 is an apocalyptic number.

It is an amenable number.

10412223433 is a deficient number, since it is larger than the sum of its proper divisors (242144775).

10412223433 is an equidigital number, since it uses as much as digits as its factorization.

10412223433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 242144774.

The product of its (nonzero) digits is 3456, while the sum is 25.

Adding to 10412223433 its reverse (33432221401), we get a palindrome (43844444834).

The spelling of 10412223433 in words is "ten billion, four hundred twelve million, two hundred twenty-three thousand, four hundred thirty-three".

Divisors: 1 43 242144731 10412223433