1041330333433 has 4 divisors (see below), whose sum is σ = 1121432666788. Its totient is φ = 961228000080.

The previous prime is 1041330333409. The next prime is 1041330333469. The reversal of 1041330333433 is 3343330331401.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 269582139369 + 771748194064 = 519213^2 + 878492^2 .

It is a cyclic number.

It is not a de Polignac number, because 1041330333433 - 2⁹ = 1041330332921 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1041330333395 and 1041330333404.

It is not an unprimeable number, because it can be changed into a prime (1041330333733) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 40051166658 + ... + 40051166683.

It is an arithmetic number, because the mean of its divisors is an integer number (280358166697).

Almost surely, 2^{1041330333433} is an apocalyptic number.

1041330333433 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

1041330333433 is a deficient number, since it is larger than the sum of its proper divisors (80102333355).

1041330333433 is an equidigital number, since it uses as much as digits as its factorization.

1041330333433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 80102333354.

The product of its (nonzero) digits is 34992, while the sum is 31.

Adding to 1041330333433 its reverse (3343330331401), we get a palindrome (4384660664834).

The spelling of 1041330333433 in words is "one trillion, forty-one billion, three hundred thirty million, three hundred thirty-three thousand, four hundred thirty-three".