1041443121141 has 12 divisors (see below), whose sum is σ = 1505683054668. Its totient is φ = 693660187584.

The previous prime is 1041443121133. The next prime is 1041443121149. The reversal of 1041443121141 is 1411213441401.

1041443121141 is a `hidden beast` number, since 1 + 0 + 4 + 1 + 443 + 1 + 211 + 4 + 1 = 666.

It is an interprime number because it is at equal distance from previous prime (1041443121133) and next prime (1041443121149).

It can be written as a sum of positive squares in 2 ways, for example, as 651999726225 + 389443394916 = 807465^2 + 624054^2 .

It is not a de Polignac number, because 1041443121141 - 2³ = 1041443121133 is a prime.

It is a super-2 number, since 2×1041443121141² (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1041443121149) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 52925160 + ... + 52944833.

It is an arithmetic number, because the mean of its divisors is an integer number (125473587889).

Almost surely, 2^{1041443121141} is an apocalyptic number.

It is an amenable number.

1041443121141 is a deficient number, since it is larger than the sum of its proper divisors (464239933527).

1041443121141 is a wasteful number, since it uses less digits than its factorization.

1041443121141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 105871092 (or 105871089 counting only the distinct ones).

The product of its (nonzero) digits is 1536, while the sum is 27.

Adding to 1041443121141 its reverse (1411213441401), we get a palindrome (2452656562542).

The spelling of 1041443121141 in words is "one trillion, forty-one billion, four hundred forty-three million, one hundred twenty-one thousand, one hundred forty-one".