104213144041 has 4 divisors (see below), whose sum is σ = 106754928084. Its totient is φ = 101671360000.

The previous prime is 104213143987. The next prime is 104213144047. The reversal of 104213144041 is 140441312401.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 140441312401 = 13 ⋅10803177877.

It can be written as a sum of positive squares in 2 ways, for example, as 23341728400 + 80871415641 = 152780^2 + 284379^2 .

It is a cyclic number.

It is not a de Polignac number, because 104213144041 - 2¹¹ = 104213141993 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 104213143997 and 104213144015.

It is not an unprimeable number, because it can be changed into a prime (104213144047) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1270891960 + ... + 1270892041.

It is an arithmetic number, because the mean of its divisors is an integer number (26688732021).

Almost surely, 2^104213144041 is an apocalyptic number.

It is an amenable number.

104213144041 is a deficient number, since it is larger than the sum of its proper divisors (2541784043).

104213144041 is an equidigital number, since it uses as much as digits as its factorization.

104213144041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2541784042.

The product of its (nonzero) digits is 1536, while the sum is 25.

Adding to 104213144041 its reverse (140441312401), we get a palindrome (244654456442).

The spelling of 104213144041 in words is "one hundred four billion, two hundred thirteen million, one hundred forty-four thousand, forty-one".