Base | Representation |
---|---|
bin | 10011011011011111… |
… | …11010101001100101 |
3 | 222220222011110222010 |
4 | 21231233322221211 |
5 | 132330342242013 |
6 | 4443025024433 |
7 | 516331561116 |
oct | 115557725145 |
9 | 28828143863 |
10 | 10431212133 |
11 | 4473169081 |
12 | 2031485119 |
13 | ca3139694 |
14 | 70d53020d |
15 | 410b897c3 |
hex | 26dbfaa65 |
10431212133 has 4 divisors (see below), whose sum is σ = 13908282848. Its totient is φ = 6954141420.
The previous prime is 10431212131. The next prime is 10431212167. The reversal of 10431212133 is 33121213401.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 33121213401 = 3 ⋅11040404467.
It is not a de Polignac number, because 10431212133 - 21 = 10431212131 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (10431212131) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1738535353 + ... + 1738535358.
It is an arithmetic number, because the mean of its divisors is an integer number (3477070712).
Almost surely, 210431212133 is an apocalyptic number.
It is an amenable number.
10431212133 is a deficient number, since it is larger than the sum of its proper divisors (3477070715).
10431212133 is an equidigital number, since it uses as much as digits as its factorization.
10431212133 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3477070714.
The product of its (nonzero) digits is 432, while the sum is 21.
Adding to 10431212133 its reverse (33121213401), we get a palindrome (43552425534).
The spelling of 10431212133 in words is "ten billion, four hundred thirty-one million, two hundred twelve thousand, one hundred thirty-three".
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