Base | Representation |
---|---|
bin | 10011011011101000… |
… | …00111100001011001 |
3 | 222221001020102200000 |
4 | 21231310013201121 |
5 | 132331133012213 |
6 | 4443104403213 |
7 | 516344125653 |
oct | 115564074131 |
9 | 28831212600 |
10 | 10432313433 |
11 | 4473850543 |
12 | 2031916509 |
13 | ca3433a39 |
14 | 70d7396d3 |
15 | 410d05c73 |
hex | 26dd07859 |
10432313433 has 48 divisors (see below), whose sum is σ = 15775119360. Its totient is φ = 6889340304.
The previous prime is 10432313407. The next prime is 10432313473. The reversal of 10432313433 is 33431323401.
10432313433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 10432313433 - 26 = 10432313369 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (27).
It is a junction number, because it is equal to n+sod(n) for n = 10432313397 and 10432313406.
It is not an unprimeable number, because it can be changed into a prime (10432313473) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 15273910 + ... + 15274592.
It is an arithmetic number, because the mean of its divisors is an integer number (328648320).
Almost surely, 210432313433 is an apocalyptic number.
It is an amenable number.
10432313433 is a deficient number, since it is larger than the sum of its proper divisors (5342805927).
10432313433 is an equidigital number, since it uses as much as digits as its factorization.
10432313433 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1200 (or 1188 counting only the distinct ones).
The product of its (nonzero) digits is 7776, while the sum is 27.
Adding to 10432313433 its reverse (33431323401), we get a palindrome (43863636834).
It can be divided in two parts, 1043 and 2313433, that added together give a triangular number (2314476 = T2151).
The spelling of 10432313433 in words is "ten billion, four hundred thirty-two million, three hundred thirteen thousand, four hundred thirty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.069 sec. • engine limits •