104331132313 has 4 divisors (see below), whose sum is σ = 109822244560. Its totient is φ = 98840020068.

The previous prime is 104331132281. The next prime is 104331132319. The reversal of 104331132313 is 313231133401.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 313231133401 = 85607 ⋅3658943.

It is a cyclic number.

It is not a de Polignac number, because 104331132313 - 2⁵ = 104331132281 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (104331132319) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2745556095 + ... + 2745556132.

It is an arithmetic number, because the mean of its divisors is an integer number (27455561140).

Almost surely, 2^104331132313 is an apocalyptic number.

It is an amenable number.

104331132313 is a deficient number, since it is larger than the sum of its proper divisors (5491112247).

104331132313 is an equidigital number, since it uses as much as digits as its factorization.

104331132313 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5491112246.

The product of its (nonzero) digits is 1944, while the sum is 25.

Adding to 104331132313 its reverse (313231133401), we get a palindrome (417562265714).

The spelling of 104331132313 in words is "one hundred four billion, three hundred thirty-one million, one hundred thirty-two thousand, three hundred thirteen".